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1652.DefusetheBomb.py
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"""
You have a bomb to defuse, and your time is running out! Your informer
will provide you with a circular array code of length of n and a key k.
To decrypt the code, you must replace every number. All the numbers are
replaced simultaneously.
- If k > 0, replace the ith number with the sum of the next k numbers.
- If k < 0, replace the ith number with the sum of the previous k
numbers.
- If k == 0, replace the ith number with 0.
As code is circular, the next element of code[n-1] is code[0], and the
previous element of code[0] is code[n-1].
Given the circular array code and an integer key k, return the decrypted
code to defuse the bomb!
Example:
Input: code = [5,7,1,4], k = 3
Output: [12,10,16,13]
Explanation: Each number is replaced by the sum of the next 3 numbers.
The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1].
Notice that the numbers wrap around.
Example:
Input: code = [1,2,3,4], k = 0
Output: [0,0,0,0]
Explanation: When k is zero, the numbers are replaced by 0.
Example:
Input: code = [2,4,9,3], k = -2
Output: [12,5,6,13]
Explanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the
numbers wrap around again. If k is negative, the sum is of
the previous numbers.
Constraints:
- n == code.length
- 1 <= n <= 100
- 1 <= code[i] <= 100
- -(n - 1) <= k <= n - 1
"""
#Difficulty: Easy
#74 / 74 test cases passed.
#Runtime: 36 ms
#Memory Usage: 14.3 MB
#Runtime: 36 ms, faster than 86.16% of Python3 online submissions for Defuse the Bomb.
#Memory Usage: 14.3 MB, less than 12.55% of Python3 online submissions for Defuse the Bomb.
class Solution:
def decrypt(self, code: List[int], k: int) -> List[int]:
length = len(code)
code += code
for i in range(length):
formula = {True : sum(code[i+1:i+1+k]), False : sum(code[i+length+k:i+length])}
code[i] = formula[k>=0]
return code[:length]